B.E.S.T. Geometry — EOC
Free Practice · 10 Questions · 20 min
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Question 1 of 10
Florida standards 1A-1GMedium Calc Word Diagram
A kite is flying at the end of a 200-foot string. The string makes a 55° angle with the ground. How high above the ground is the kite? Round to the nearest foot. (sin 55° ≈ 0.819) h = ?55°200 ft
A186 feet
B141 feet
C115 feet
D164 feet
Explanation
📌 Step 1: Identify the trig ratio
We know the hypotenuse (200 ft) and want the opposite side (height).
Use sine: sin = opposite / hypotenuse

📌 Step 2: Set up and solve
sin(55°) = h / 200
0.819 = h / 200
h = 200 × 0.819 = 163.8

📌 Answer:164 feet

💡 Tip: Angle of elevation from ground = angle between the string and the horizontal, NOT the vertical.
Question 2 of 10
Florida standards 8A-8BHard Calc Word Diagram
In right triangle ABC, an altitude CD is drawn from the right angle C to hypotenuse AB. If AD = 5 and DB = 12, what is the length of CD? ABCD512h = ?Geometric Mean
A2√15 ≈ 7.75
B√17 ≈ 4.12
C√85 ≈ 9.22
D8.5
Explanation
The altitude to the hypotenuse is the geometric mean of the two segments:
CD = √(AD × DB) = √(5 × 12) = √60 = 2√15 ≈ 7.75.
Question 3 of 10
Florida standards 1A-1GMedium Calc Word Diagram
A zip-line connects the top of a 40-foot platform to a point on the ground 75 feet away. What is the length of the zip-line cable? 40 ft75 ftcable = ?
A75 feet
B95 feet
C85 feet
D80 feet
Explanation
📌 Step 1: Identify the right triangle
The platform height (40 ft), ground distance (75 ft), and cable form a right triangle.

📌 Step 2: Apply the Pythagorean Theorem
cable² = 40² + 75²
cable² = 1600 + 5625
cable² = 7225

📌 Step 3: Solve
cable = √7225 = 85 ft

💡 Tip: This is a multiple of the 8-15-17 Pythagorean triple (×5 = 40-75-85).
Question 4 of 10
Florida standards 11A-11DMedium Calc Word Diagram
A swimming pool has the shape shown below — a rectangle with a semicircle on each end. Find the total area of the pool. (Use π ≈ 3.14) 20 m10 mr = 5
A356.0 m²
B278.5 m²
C200.0 m²
D257.0 m²
Explanation
Rectangle area = 20 × 10 = 200 m².
Two semicircles = one full circle with r = 5: π × 5² = 3.14 × 25 = 78.5 m².
Total = 200 + 78.5 = 278.5 m².
Question 5 of 10
Florida standards 11A-11DMedium Calc Word Diagram
Find the volume of the cone shown below. Round to the nearest tenth. (Use π ≈ 3.14) h = 15 cmr = 6 cm
A1695.6 cm³
B339.1 cm³
C452.2 cm³
D565.2 cm³
Explanation
📌 Step 1: Recall the cone volume formula
V = (1/3)πr²h

📌 Step 2: Plug in values
r = 6 cm, h = 15 cm
V = (1/3)(3.14)(36)(15)

📌 Step 3: Calculate step by step
3.14 × 36 = 113.04
113.04 × 15 = 1695.6
1695.6 / 3 = 565.2 cm³

💡 Common mistake: Don't forget to divide by 3! A cone is 1/3 the volume of a cylinder with the same base and height.
Question 6 of 10
Florida standards 1A-1GEasy Calc Word
A pizza box is 14 inches on each side and 2 inches tall. What is the volume of the box?
A448 in³
B392 in³
C280 in³
D196 in³
Explanation
📌 Step 1: Identify the shape
A pizza box is a rectangular prism (cuboid).

📌 Step 2: Apply the volume formula
V = length × width × height
V = 14 × 14 × 2

📌 Step 3: Calculate
= 392 in³

💡 Quick check: Volume is always in cubic units. If your answer is in square units, something went wrong!
Question 7 of 10
Florida standards 1A-1GHard Calc Word
A flagpole casts a shadow 15 feet long. At the same time, a 6-foot person standing nearby casts a shadow 4 feet long. How tall is the flagpole?
A22.5 feet
B18.0 feet
C20.0 feet
D24.0 feet
Explanation
📌 Step 1: Recognize similar triangles
The sun creates the same angle for both the flagpole and the person, making two similar triangles.

📌 Step 2: Set up the proportion
flagpole height / flagpole shadow = person height / person shadow
h / 15 = 6 / 4

📌 Step 3: Cross-multiply and solve
h × 4 = 15 × 6
4h = 90
h = 22.5 feet

💡 Tip: Shadow problems always use similar triangles because the sun's rays are parallel.
Question 8 of 10
Florida standards 7A-7BMedium Calc Word Diagram
A tree casts a shadow 18 feet long. At the same time, a 5-foot-tall fence post casts a shadow 3 feet long. How tall is the tree? h = ?18 ft5 ft3 ftSimilar triangles (AA)
A27 feet
B24 feet
C30 feet
D36 feet
Explanation
The tree and fence post form similar triangles with their shadows (same sun angle).
tree height / tree shadow = fence height / fence shadow
h / 18 = 5 / 3
h = 18 × 5/3 = 30 feet.
Question 9 of 10
Florida standards 4A-4DEasy Calc Word Diagram
Jake claims: "If a quadrilateral has four right angles, then it must be a square." Which figure below is a counterexample? A. Square60×60B. Rectangle90×60C. RhombusD. Trapezoid
ARhombus
BSquare
CRectangle
DTrapezoid
Explanation
A rectangle has four right angles but is NOT necessarily a square (it can have unequal side lengths).
The rectangle with sides 90×60 is a counterexample to Jake's claim.
Question 10 of 10
Florida standards 3A-3DEasy Calc Word Diagram
Which of the following figures has BOTH reflectional and rotational symmetry? ABCD
AB (Regular hexagon)
BA (Scalene triangle)
CC (Parallelogram)
DD (Arrow)
Explanation
📌 Step 1: Check each figure

A (Scalene triangle): No lines of symmetry, no rotational symmetry ✗
B (Regular hexagon): 6 lines of symmetry + rotational symmetry at 60° ✓
C (Parallelogram): No lines of symmetry, rotational symmetry at 180° only → partial ✗
D (Arrow): 1 line of symmetry (vertical) but no rotational symmetry ✗

📌 Answer: B (Regular hexagon)

💡 Tip: All regular polygons have BOTH reflectional AND rotational symmetry. The number of symmetry lines = number of sides.

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